What is the answer to log_{7}(x^3-3x^2+3x-1)=6 ?

The answer to log_{7}(x^3-3x^2+3x-1)=6 is x=50

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log_{7}(x^3-3x^2+3x-1)=6

lo g_{7} (x^{3} - 3 x^{2} + 3 x - 1) = 6

x = 50

Solution steps

lo g_{7} (x^{3} - 3 x^{2} + 3 x - 1) = 6

Apply log rules

x^{3} - 3 x^{2} + 3 x - 1 = 117649

Solve

x^{3} - 3 x^{2} + 3 x - 1 = 117649 : x = 50

x = 50

3 ln (2 x) = 15

3 ln (2 x) = 12

3 ln (5 x - 1) + 17 = 29

lo g_{5} (x + 2) + lo g_{5} (x) = 1.5

ln^{3} (x) + 3 ln^{2} (x) = 0

What is the answer to log_{7}(x^3-3x^2+3x-1)=6 ?
The answer to log_{7}(x^3-3x^2+3x-1)=6 is x=50
Solve for x: log_{7}(x^3-3x^2+3x-1)=6
The solution is x=50