What is the answer to 3ln(5x-1)+17=29 ?

The answer to 3ln(5x-1)+17=29 is x=(e^4+1)/5

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3ln(5x-1)+17=29

3 ln (5 x - 1) + 17 = 29

x = \frac{e ^{4} + 1}{5}

Decimal Notation

x = 11.11963 \dots

Solution steps

3 ln (5 x - 1) + 17 = 29

Move

17

to the right side

3 ln (5 x - 1) = 12

Divide both sides by

3

ln (5 x - 1) = 4

Apply log rules

5 x - 1 = e^{4}

Solve

5 x - 1 = e^{4} : x = \frac{e ^{4} + 1}{5}

x = \frac{e ^{4} + 1}{5}

Verify Solutions:

x = \frac{e ^{4} + 1}{5}

True

The solution is

x = \frac{e ^{4} + 1}{5}

lo g_{5} (x + 2) + lo g_{5} (x) = 1.5

ln^{3} (x) + 3 ln^{2} (x) = 0

ln (3 x - 16) = 9

x, ln (e^{x y}) = ln (1)

ln (3 x - 16) = 6

What is the answer to 3ln(5x-1)+17=29 ?
The answer to 3ln(5x-1)+17=29 is x=(e^4+1)/5
Solve for x: 3ln(5x-1)+17=29
The solution is x=(e^4+1)/5