What is the answer to solvefor x,ln(e^{xy})=ln(1) ?

The answer to solvefor x,ln(e^{xy})=ln(1) is x=0

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solvefor x,ln(e^{xy})=ln(1)

solve for

x, ln (e^{x y}) = ln (1)

x = 0

Solution steps

ln (e^{x y}) = ln (1)

Apply log rules

e^{x y} = 1

Solve

e^{x y} = 1 : x = 0

x = 0

Verify Solutions:

x = 0

True

The solution is

x = 0

ln (3 x - 16) = 6

20 lo g_{10} (\frac{x}{1}) = 30

0 = 2 x + ln (x)

lo g_{10} (2 X + 50) = 2

0 = lo g_{2} (x^{2} - 16)

What is the answer to solvefor x,ln(e^{xy})=ln(1) ?
The answer to solvefor x,ln(e^{xy})=ln(1) is x=0