What is the answer to 0=log_{2}(x^2-16) ?

The answer to 0=log_{2}(x^2-16) is x=sqrt(17),x=-sqrt(17)

Solve for x: 0=log_{2}(x^2-16)

The solution is x=sqrt(17),x=-sqrt(17)

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0 = lo g_{2} (x^{2} - 16)

x = 17, x = - 17

Decimal Notation

x = 4.12310 \dots, x = - 4.12310 \dots

Solution steps

0 = lo g_{2} (x^{2} - 16)

Apply log rules

1 = x^{2} - 16

Solve

1 = x^{2} - 16 : x = 17, x = - 17

x = 17, x = - 17

ln (x^{2} + 2) - ln (x - 4) = 7

0.7 = lo g_{2} (\frac{x}{32000})

lo g_{4} (x + 5) + lo g_{4} (x - 1) = 2

ln (x) + ln (0.2) = ln (e)

lo g_{10} (36) + lo g_{10} (x) = 34

What is the answer to 0=log_{2}(x^2-16) ?
The answer to 0=log_{2}(x^2-16) is x=sqrt(17),x=-sqrt(17)
Solve for x: 0=log_{2}(x^2-16)
The solution is x=sqrt(17),x=-sqrt(17)