What is the answer to 0.367=2-log_{10}(x) ?

The answer to 0.367=2-log_{10}(x) is x=10^{1.633}

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0.367=2-log_{10}(x)

0.367 = 2 - lo g_{10} (x)

x = 1 0^{1.633}

Decimal Notation

x = 42.95364 \dots

Solution steps

0.367 = 2 - lo g_{10} (x)

Move

lo g_{10} (x)

to the left side

0.367 + lo g_{10} (x) = 2

Move

0.367

to the right side

lo g_{10} (x) = 1.633

Apply log rules

x = 1 0^{1.633}

Verify Solutions:

x = 1 0^{1.633}

True

The solution is

x = 1 0^{1.633}

lo g_{a} (64) = - 2

x + lo g_{10} (x + 4) = 6

lo g_{2} (9 x + 12) - lo g_{2} (3) = 4

3 = lo g_{10} (p (x)) (24 x - 18 x^{2})

ln (x - 2) = 0.5

What is the answer to 0.367=2-log_{10}(x) ?
The answer to 0.367=2-log_{10}(x) is x=10^{1.633}
Solve for x: 0.367=2-log_{10}(x)
The solution is x=10^{1.633}