What is the answer to log_{2}(x)+log_{2}(8x)=2 ?

The answer to log_{2}(x)+log_{2}(8x)=2 is x= 1/(sqrt(2))

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log_{2}(x)+log_{2}(8x)=2

lo g_{2} (x) + lo g_{2} (8 x) = 2

x = \frac{1}{2}

Decimal Notation

x = 0.70710 \dots

Solution steps

lo g_{2} (x) + lo g_{2} (8 x) = 2

Apply log rules

x = \frac{1}{2}

Verify Solutions:

x = \frac{1}{2}

True

The solution is

x = \frac{1}{2}

lo g_{5} (x) - 2 lo g_{x} (5) = 3

lo g_{5} (x) - lo g_{5} (2) = 2

lo g_{x} (0.001) = - 3

lo g_{2} (x + 5) + lo g_{2} (x - 5) = 6

x, z = ln (x y)

What is the answer to log_{2}(x)+log_{2}(8x)=2 ?
The answer to log_{2}(x)+log_{2}(8x)=2 is x= 1/(sqrt(2))
Solve for x: log_{2}(x)+log_{2}(8x)=2
The solution is x= 1/(sqrt(2))