What is the answer to log_{2}(x+5)+log_{2}(x-5)=6 ?

The answer to log_{2}(x+5)+log_{2}(x-5)=6 is x=sqrt(89)

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log_{2}(x+5)+log_{2}(x-5)=6

lo g_{2} (x + 5) + lo g_{2} (x - 5) = 6

x = 89

Decimal Notation

x = 9.43398 \dots

Solution steps

lo g_{2} (x + 5) + lo g_{2} (x - 5) = 6

Apply log rules

(x + 5) (x - 5) = 64

Solve

(x + 5) (x - 5) = 64 : x = 89, x = - 89

x = 89, x = - 89

Verify Solutions:

x = 89

True

, x = - 89

False

The solution is

x = 89

x, z = ln (x y)

lo g_{10} (x) = 4.9

\frac{ln ( 2 x )}{ln ( 4 x )} = 4

lo g_{x} (4) = \frac{- 1}{2}

62 = 10 lo g_{10} (\frac{85}{x})

What is the answer to log_{2}(x+5)+log_{2}(x-5)=6 ?
The answer to log_{2}(x+5)+log_{2}(x-5)=6 is x=sqrt(89)
Solve for x: log_{2}(x+5)+log_{2}(x-5)=6
The solution is x=sqrt(89)