What is the answer to ln(1+b)=(6.67*10^{-4}) ?

The answer to ln(1+b)=(6.67*10^{-4}) is b=e^{(6.67)/(10000)}-1

Solve for b: ln(1+b)=(6.67*10^{-4})

The solution is b=e^{(6.67)/(10000)}-1

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ln (1 + b) = (6.67 \cdot 1 0^{- 4})

b = e^{\frac{6.67}{10000}} - 1

Decimal Notation

b = 0.00066 \dots

Solution steps

ln (1 + b) = (6.67 \cdot 1 0^{- 4})

Apply log rules

1 + b = e^{\frac{6.67}{10000}}

Solve

1 + b = e^{\frac{6.67}{10000}} : b = e^{\frac{6.67}{10000}} - 1

b = e^{\frac{6.67}{10000}} - 1

\frac{ln ( 2 x - 5 )}{2} = ln (x - 2)

ln (x) \cdot e = 0

ln (7 - 4 x) = 10

lo g_{10} (x^{2}) = 2.0279

0 = 1 - ln (x)

What is the answer to ln(1+b)=(6.67*10^{-4}) ?
The answer to ln(1+b)=(6.67*10^{-4}) is b=e^{(6.67)/(10000)}-1
Solve for b: ln(1+b)=(6.67*10^{-4})
The solution is b=e^{(6.67)/(10000)}-1