What is the answer to log_{10}(x^2-16x+1)=0 ?

The answer to log_{10}(x^2-16x+1)=0 is x=16,x=0

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log_{10}(x^2-16x+1)=0

lo g_{10} (x^{2} - 16 x + 1) = 0

x = 16, x = 0

Solution steps

lo g_{10} (x^{2} - 16 x + 1) = 0

Apply log rules

x^{2} - 16 x + 1 = 1

Solve

x^{2} - 16 x + 1 = 1 : x = 16, x = 0

x = 16, x = 0

2 ln (3 x^{2} + 1) = 13

ln (15 - 2 x) = 2 ln (x)

1 = 3 lo g_{10} (4 x + 10)

lo g_{6} (9 x) - 2 lo g_{6} (2) = 3

lo g_{7} (2 x - 3) = 2

What is the answer to log_{10}(x^2-16x+1)=0 ?
The answer to log_{10}(x^2-16x+1)=0 is x=16,x=0
Solve for x: log_{10}(x^2-16x+1)=0
The solution is x=16,x=0