What is the answer to ln(2x)+ln(3x)=15 ?

The answer to ln(2x)+ln(3x)=15 is x=e^{(15-ln(6))/2}

Solve for x: ln(2x)+ln(3x)=15

The solution is x=e^{(15-ln(6))/2}

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ln (2 x) + ln (3 x) = 15

x = e^{\frac{15 - l n ( 6 )}{2}}

Decimal Notation

x = 738.13022 \dots

Solution steps

ln (2 x) + ln (3 x) = 15

Apply log rules

x = e^{\frac{15 - l n ( 6 )}{2}}

Verify Solutions:

x = e^{\frac{15 - l n ( 6 )}{2}}

True

The solution is

x = e^{\frac{15 - l n ( 6 )}{2}}

14 lo g_{10} (x^{2} - x - 6) = 1

2 lo g_{10} (x + 2) = x

4 = 5 lo g_{10} (x) - lo g_{2} (x)

lo g_{2} (x + 1) = - 3

4 (lo g_{5} (x) + lo g_{x} (5)) = 10

What is the answer to ln(2x)+ln(3x)=15 ?
The answer to ln(2x)+ln(3x)=15 is x=e^{(15-ln(6))/2}
Solve for x: ln(2x)+ln(3x)=15
The solution is x=e^{(15-ln(6))/2}