What is the answer to solvefor x,In(log_{x}(3))=2 ?

The answer to solvefor x,In(log_{x}(3))=2 is x=3^{(nI)/2}

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solvefor x,In(log_{x}(3))=2

solve for

x, I n (lo g_{x} (3)) = 2

x = 3^{\frac{n I}{2}}

Solution steps

I n (lo g_{x} (3)) = 2

Divide both sides by

I n

lo g_{x} (3) = \frac{2}{I n}

Apply log rules

\frac{1}{lo g _{3} ( x )} = \frac{2}{I n}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

1 \cdot I n = lo g_{3} (x) \cdot 2

Simplify

n I = lo g_{3} (x) \cdot 2

Switch sides

lo g_{3} (x) \cdot 2 = n I

Divide both sides by

2

lo g_{3} (x) = \frac{n I}{2}

Apply log rules

x = 3^{\frac{n I}{2}}

\frac{lo g _{4} ( 15 x + 1 ) 1}{2} = 2

lo g_{x} (243) = - 5

lo g_{2} (2 x - 1) = 4

x, lo g_{3} (4 x - 1) = 3

lo g_{4} (x) + lo g_{4} (2) = 2

What is the answer to solvefor x,In(log_{x}(3))=2 ?
The answer to solvefor x,In(log_{x}(3))=2 is x=3^{(nI)/2}