What is the answer to log_{2}(2x-1)=4 ?

The answer to log_{2}(2x-1)=4 is x= 17/2

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log_{2}(2x-1)=4

lo g_{2} (2 x - 1) = 4

x = \frac{17}{2}

Decimal Notation

x = 8.5

Solution steps

lo g_{2} (2 x - 1) = 4

Apply log rules

2 x - 1 = 16

Solve

2 x - 1 = 16 : x = \frac{17}{2}

x = \frac{17}{2}

x, lo g_{3} (4 x - 1) = 3

lo g_{4} (x) + lo g_{4} (2) = 2

0 = 34.2 - 5.7 ln (x)

ln (3 t + 1) + ln (3 t - 1) = 0

ln (5 x) = 1.7

What is the answer to log_{2}(2x-1)=4 ?
The answer to log_{2}(2x-1)=4 is x= 17/2
Solve for x: log_{2}(2x-1)=4
The solution is x= 17/2