What is the answer to log_{3}(x+2)=log_{3}(x-4)+2 ?

The answer to log_{3}(x+2)=log_{3}(x-4)+2 is x= 19/4

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log_{3}(x+2)=log_{3}(x-4)+2

lo g_{3} (x + 2) = lo g_{3} (x - 4) + 2

x = \frac{19}{4}

Decimal Notation

x = 4.75

Solution steps

lo g_{3} (x + 2) = lo g_{3} (x - 4) + 2

Apply log rules

x + 2 = (x - 4) \cdot 9

Solve

x + 2 = (x - 4) \cdot 9 : x = \frac{19}{4}

x = \frac{19}{4}

Verify Solutions:

x = \frac{19}{4}

True

The solution is

x = \frac{19}{4}

20 lo g_{10} (x) = 45

lo g_{2} (5 x + 5) = 2

lo g_{2} (5 x + 5) = 5

lo g_{2} (x + 1) = 0

lo g_{d} (5) = \frac{1}{2}

What is the answer to log_{3}(x+2)=log_{3}(x-4)+2 ?
The answer to log_{3}(x+2)=log_{3}(x-4)+2 is x= 19/4
Solve for x: log_{3}(x+2)=log_{3}(x-4)+2
The solution is x= 19/4