What is the answer to log_{2}(5x+5)=5 ?

The answer to log_{2}(5x+5)=5 is x= 27/5

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log_{2}(5x+5)=5

lo g_{2} (5 x + 5) = 5

x = \frac{27}{5}

Decimal Notation

x = 5.4

Solution steps

lo g_{2} (5 x + 5) = 5

Apply log rules

5 x + 5 = 32

Solve

5 x + 5 = 32 : x = \frac{27}{5}

x = \frac{27}{5}

lo g_{2} (x + 1) = 0

lo g_{d} (5) = \frac{1}{2}

ln (2 x + 5) - ln (x) = 4

1 - lo g_{2} (1 - x^{2}) = 2

4 + ln (27 x) = 22 - 2 ln (x)

What is the answer to log_{2}(5x+5)=5 ?
The answer to log_{2}(5x+5)=5 is x= 27/5
Solve for x: log_{2}(5x+5)=5
The solution is x= 27/5