What is factor y^2+3y-4 ?

The solution to factor y^2+3y-4 is (y-1)(y+4)

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factor y^2+3y-4

factor

y^{2} + 3 y - 4

(y - 1) (y + 4)

Solution steps

y^{2} + 3 y - 4

Break the expression into groups

= (y^{2} - y) + (4 y - 4)

Factor out

y

from

y^{2} - y : y (y - 1)

Factor out

4

from

4 y - 4 : 4 (y - 1)

= y (y - 1) + 4 (y - 1)

Factor out common term

y - 1

= (y - 1) (y + 4)

x^{2} = 4 x + 32

x^{2} + 6 x + 9 = x + 45

\frac{3 x ^{- 2}}{y ^{5} w ^{- 2}}

ln (e^{2}) = x

3.1 x^{2} - 5.2 x + 1.7 = 0