What is the answer to ln(3)+ln(x+1)=-1 ?

The answer to ln(3)+ln(x+1)=-1 is x= 1/(3e)-1

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ln(3)+ln(x+1)=-1

ln (3) + ln (x + 1) = - 1

x = \frac{1}{3 e} - 1

Decimal Notation

x = - 0.87737 \dots

Solution steps

ln (3) + ln (x + 1) = - 1

Move

ln (3)

to the right side

ln (x + 1) = - 1 - ln (3)

Apply log rules

x + 1 = \frac{1}{3 e}

Solve

x + 1 = \frac{1}{3 e} : x = \frac{1}{3 e} - 1

x = \frac{1}{3 e} - 1

Verify Solutions:

x = \frac{1}{3 e} - 1

True

The solution is

x = \frac{1}{3 e} - 1

lo g_{2} (x) + lo g_{2} (4) = 3

lo g_{2} (x - 1) = 4 - lo g_{2} (3)

ln (5 - x) = ln (5) - ln (x)

a, lo g_{b} (a) = c

a, lo g_{b} (a) = 1

What is the answer to ln(3)+ln(x+1)=-1 ?
The answer to ln(3)+ln(x+1)=-1 is x= 1/(3e)-1
Solve for x: ln(3)+ln(x+1)=-1
The solution is x= 1/(3e)-1