What is the answer to log_{4}(log_{4}(2x))=1 ?

The answer to log_{4}(log_{4}(2x))=1 is x=128

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log_{4}(log_{4}(2x))=1

lo g_{4} (lo g_{4} (2 x)) = 1

x = 128

Solution steps

lo g_{4} (lo g_{4} (2 x)) = 1

Apply log rules

2 x = 256

Solve

2 x = 256 : x = 128

x = 128

Verify Solutions:

x = 128

True

The solution is

x = 128

lo g_{10} (x - 1) + lo g_{10} (5 x) = 2

50 = 0.5 x + 2 ln (x)

lo g_{6} (- 3 x) + lo g_{6} (- 10 x) = 5

5 + ln (x - 5) = 2

x, 3 x + y + ln (x y) = C

What is the answer to log_{4}(log_{4}(2x))=1 ?
The answer to log_{4}(log_{4}(2x))=1 is x=128
Solve for x: log_{4}(log_{4}(2x))=1
The solution is x=128