What is the answer to log_{6}(x)+log_{6}(5x-1)=1 ?

The answer to log_{6}(x)+log_{6}(5x-1)=1 is x= 6/5

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log_{6}(x)+log_{6}(5x-1)=1

lo g_{6} (x) + lo g_{6} (5 x - 1) = 1

x = \frac{6}{5}

Decimal Notation

x = 1.2

Solution steps

lo g_{6} (x) + lo g_{6} (5 x - 1) = 1

Apply log rules

x (5 x - 1) = 6

Solve

x (5 x - 1) = 6 : x = \frac{6}{5}, x = - 1

x = \frac{6}{5}, x = - 1

Verify Solutions:

x = \frac{6}{5}

True

, x = - 1

False

The solution is

x = \frac{6}{5}

lo g_{10} (3) + lo g_{10} (x - 7) = 1

lo g_{10} (x) = 1.5306

x, Z = x y + ln (x + y)

61 = lo g_{10} (\frac{100}{x})

ln (x) = 4.123

What is the answer to log_{6}(x)+log_{6}(5x-1)=1 ?
The answer to log_{6}(x)+log_{6}(5x-1)=1 is x= 6/5
Solve for x: log_{6}(x)+log_{6}(5x-1)=1
The solution is x= 6/5