What is the answer to log_{2}(4x)+log_{2}(2)=4 ?

The answer to log_{2}(4x)+log_{2}(2)=4 is x=2

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log_{2}(4x)+log_{2}(2)=4

lo g_{2} (4 x) + lo g_{2} (2) = 4

x = 2

Solution steps

lo g_{2} (4 x) + lo g_{2} (2) = 4

Move

lo g_{2} (2)

to the right side

lo g_{2} (4 x) = 4 - lo g_{2} (2)

Apply log rules

4 x = 8

Solve

4 x = 8 : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

ln (5) = 1 + ln (2 x)

2 ln (x - 1) - ln (x) = 1

x, lo g_{e} (2 x - 1) = - 3

lo g_{2} (- 5 x + 8) = 1

1.5 n^{2} - 7.5 n lo g_{10} (n) = 0

What is the answer to log_{2}(4x)+log_{2}(2)=4 ?
The answer to log_{2}(4x)+log_{2}(2)=4 is x=2
Solve for x: log_{2}(4x)+log_{2}(2)=4
The solution is x=2