What is the answer to log_{8}(x-8)+log_{8}(7)=2 ?

The answer to log_{8}(x-8)+log_{8}(7)=2 is x= 120/7

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log_{8}(x-8)+log_{8}(7)=2

lo g_{8} (x - 8) + lo g_{8} (7) = 2

x = \frac{120}{7}

Decimal Notation

x = 17.14285 \dots

Solution steps

lo g_{8} (x - 8) + lo g_{8} (7) = 2

Move

lo g_{8} (7)

to the right side

lo g_{8} (x - 8) = 2 - lo g_{8} (7)

Apply log rules

x - 8 = \frac{64}{7}

Solve

x - 8 = \frac{64}{7} : x = \frac{120}{7}

x = \frac{120}{7}

Verify Solutions:

x = \frac{120}{7}

True

The solution is

x = \frac{120}{7}

lo g_{a} (4) = 1.585, lo g_{a} (36)

lo g_{e} (x + 2) = 3

lo g_{2} (5 x + 2) = 3

lo g_{6} (x - 4) + lo g_{6} (x - 5) = 1

lo g_{10} (x) (x^{2}) = x^{3}

What is the answer to log_{8}(x-8)+log_{8}(7)=2 ?
The answer to log_{8}(x-8)+log_{8}(7)=2 is x= 120/7
Solve for x: log_{8}(x-8)+log_{8}(7)=2
The solution is x= 120/7