What is the answer to ln(x^2)=7 ?

The answer to ln(x^2)=7 is x=e^3sqrt(e),x=-e^3sqrt(e)

Solve for x: ln(x^2)=7

The solution is x=e^3sqrt(e),x=-e^3sqrt(e)

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ln (x^{2}) = 7

x = e^{3} e, x = - e^{3} e

Decimal Notation

x = 33.11545 \dots, x = - 33.11545 \dots

Solution steps

ln (x^{2}) = 7

Apply log rules

x^{2} = e^{7}

Solve

x^{2} = e^{7} : x = e^{3} e, x = - e^{3} e

x = e^{3} e, x = - e^{3} e

lo g_{x} (3) = \frac{1}{6}

x^{1 + l o g_{7} (x)} = 7 x

lo g_{10} (33 - x) = 1 + lo g_{10} (x)

3 lo g_{x} (3) = 8 - 4 lo g_{3} (x)

lo g_{3} (lo g_{2} (x)) = - 1

What is the answer to ln(x^2)=7 ?
The answer to ln(x^2)=7 is x=e^3sqrt(e),x=-e^3sqrt(e)
Solve for x: ln(x^2)=7
The solution is x=e^3sqrt(e),x=-e^3sqrt(e)