What is the answer to log_{10}(33-x)=1+log_{10}(x) ?

The answer to log_{10}(33-x)=1+log_{10}(x) is x=3

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log_{10}(33-x)=1+log_{10}(x)

lo g_{10} (33 - x) = 1 + lo g_{10} (x)

x = 3

Solution steps

lo g_{10} (33 - x) = 1 + lo g_{10} (x)

Apply log rules

33 - x = 10 x

Solve

33 - x = 10 x : x = 3

x = 3

Verify Solutions:

x = 3

True

The solution is

x = 3

3 lo g_{x} (3) = 8 - 4 lo g_{3} (x)

lo g_{3} (lo g_{2} (x)) = - 1

3 ln (x) = ln (216)

5 = lo g_{4} (x) + lo g_{4} (x) + 1

lo g_{2} (2 x + 3) - lo g_{2} (x) = 3

What is the answer to log_{10}(33-x)=1+log_{10}(x) ?
The answer to log_{10}(33-x)=1+log_{10}(x) is x=3
Solve for x: log_{10}(33-x)=1+log_{10}(x)
The solution is x=3