What is the answer to log_{10}((x+1)^2)=4 ?

The answer to log_{10}((x+1)^2)=4 is x=99,x=-101

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log_{10}((x+1)^2)=4

lo g_{10} ((x + 1)^{2}) = 4

x = 99, x = - 101

Solution steps

lo g_{10} ((x + 1)^{2}) = 4

Apply log rules

(x + 1)^{2} = 10000

Solve

(x + 1)^{2} = 10000 : x = 99, x = - 101

x = 99, x = - 101

lo g_{32} (x) = \frac{4}{5}

y + lo g_{10} (y) = 10

3 lo g_{b} (a - x) = a + c

lo g_{2} (x^{2} + 4) = 3

ln (1 + x) - ln (1 - x) = 1

What is the answer to log_{10}((x+1)^2)=4 ?
The answer to log_{10}((x+1)^2)=4 is x=99,x=-101
Solve for x: log_{10}((x+1)^2)=4
The solution is x=99,x=-101