What is the answer to y+log_{10}(y)=10 ?

The answer to y+log_{10}(y)=10 is y=(\W_{0}(ln(10)*10^{10}))/(ln(10))

Solve for y: y+log_{10}(y)=10

The solution is y=(\W_{0}(ln(10)*10^{10}))/(ln(10))

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y + lo g_{10} (y) = 10

y = \frac{W _{0} ( ln ( 10 ) \cdot 1 0 ^{10} )}{ln ( 10 )}

Decimal Notation

y = 9.04365 \dots

Solution steps

y + lo g_{10} (y) = 10

Move

y

to the right side

lo g_{10} (y) = 10 - y

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

1 0^{l o g_{10} (y)} = 1 0^{10 - y}

Simplify

1 0^{l o g_{10} (y)} : y

y = 1 0^{10 - y}

Solve

y = 1 0^{10 - y} : y = \frac{W _{0} ( ln ( 10 ) \cdot 1 0 ^{10} )}{ln ( 10 )}

y = \frac{W _{0} ( ln ( 10 ) \cdot 1 0 ^{10} )}{ln ( 10 )}

Verify Solutions:

y = \frac{W _{0} ( ln ( 10 ) \cdot 1 0 ^{10} )}{ln ( 10 )}

True

The solution is

y = \frac{W _{0} ( ln ( 10 ) \cdot 1 0 ^{10} )}{ln ( 10 )}

3 lo g_{b} (a - x) = a + c

lo g_{2} (x^{2} + 4) = 3

ln (1 + x) - ln (1 - x) = 1

lo g_{10} (x) = - 1

lo g_{3} (x) + lo g_{3} (x + 1) = 8

What is the answer to y+log_{10}(y)=10 ?
The answer to y+log_{10}(y)=10 is y=(\W_{0}(ln(10)*10^{10}))/(ln(10))
Solve for y: y+log_{10}(y)=10
The solution is y=(\W_{0}(ln(10)*10^{10}))/(ln(10))