What is the answer to ln(log_{2}(a-3))=log_{3}(1) ?

The answer to ln(log_{2}(a-3))=log_{3}(1) is a=5

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ln(log_{2}(a-3))=log_{3}(1)

ln (lo g_{2} (a - 3)) = lo g_{3} (1)

a = 5

Solution steps

ln (lo g_{2} (a - 3)) = lo g_{3} (1)

Apply log rules

a - 3 = 2

Solve

a - 3 = 2 : a = 5

a = 5

Verify Solutions:

a = 5

True

The solution is

a = 5

2 lo g_{3} (y - 2) - lo g_{3} (y - 4) = 2

lo g_{16} (x) = - \frac{1}{2}

- 5 = lo g_{10} (x)

ln (x + 1) + ln (x - 1) = 1

ln (x + 1) + ln (x - 1) = 0

What is the answer to ln(log_{2}(a-3))=log_{3}(1) ?
The answer to ln(log_{2}(a-3))=log_{3}(1) is a=5
Solve for a: ln(log_{2}(a-3))=log_{3}(1)
The solution is a=5