What is the answer to log_{10}(x-3)9=2 ?

The answer to log_{10}(x-3)9=2 is x=10^{2/9}+3

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log_{10}(x-3)9=2

lo g_{10} (x - 3) 9 = 2

x = 1 0^{\frac{2}{9}} + 3

Decimal Notation

x = 4.66810 \dots

Solution steps

lo g_{10} (x - 3) \cdot 9 = 2

Divide both sides by

9

lo g_{10} (x - 3) = \frac{2}{9}

Apply log rules

x - 3 = 1 0^{\frac{2}{9}}

Solve

x - 3 = 1 0^{\frac{2}{9}} : x = 1 0^{\frac{2}{9}} + 3

x = 1 0^{\frac{2}{9}} + 3

Verify Solutions:

x = 1 0^{\frac{2}{9}} + 3

True

The solution is

x = 1 0^{\frac{2}{9}} + 3

lo g_{3} (6 x) + lo g_{3} (2) = 3

x, ln (y) = - 3 ln (x) + c

lo g_{3} (4 x + 10) = lo g_{3} (x + 1)

\frac{ln ( 2 x - 5 )}{2} = 6

ln (t) - 66125 = - 0.07 t

What is the answer to log_{10}(x-3)9=2 ?
The answer to log_{10}(x-3)9=2 is x=10^{2/9}+3
Solve for x: log_{10}(x-3)9=2
The solution is x=10^{2/9}+3