What is the answer to log_{5}(7x)-3log_{5}(3)=0 ?

The answer to log_{5}(7x)-3log_{5}(3)=0 is x= 27/7

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log_{5}(7x)-3log_{5}(3)=0

lo g_{5} (7 x) - 3 lo g_{5} (3) = 0

x = \frac{27}{7}

Decimal Notation

x = 3.85714 \dots

Solution steps

lo g_{5} (7 x) - 3 lo g_{5} (3) = 0

Move

3 lo g_{5} (3)

to the right side

lo g_{5} (7 x) = 3 lo g_{5} (3)

Apply log rules

7 x = 27

Solve

7 x = 27 : x = \frac{27}{7}

x = \frac{27}{7}

Verify Solutions:

x = \frac{27}{7}

True

The solution is

x = \frac{27}{7}

64 x lo g_{2} (x) = 8 x^{2}

x, ln (x) - ln (x + 1) = 1

x, lo g_{3} (x + 5) = 2

lo g_{10} (x^{2} - 4 x + 5) = 0

ln (x) = lo g_{x} (e)

What is the answer to log_{5}(7x)-3log_{5}(3)=0 ?
The answer to log_{5}(7x)-3log_{5}(3)=0 is x= 27/7
Solve for x: log_{5}(7x)-3log_{5}(3)=0
The solution is x= 27/7