What is the answer to solvefor x,ln(x)-ln(x+1)=1 ?

The answer to solvefor x,ln(x)-ln(x+1)=1 is No Solution for x\in\mathbb{R}

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solvefor x,ln(x)-ln(x+1)=1

solve for

x, ln (x) - ln (x + 1) = 1

No Solution for x \in R

Solution steps

ln (x) - ln (x + 1) = 1

Add

ln (x + 1)

to both sides

ln (x) - ln (x + 1) + ln (x + 1) = 1 + ln (x + 1)

Simplify

ln (x) = 1 + ln (x + 1)

Apply log rules

x = e (x + 1)

Solve

x = e (x + 1) : x = \frac{e}{1 - e}

x = \frac{e}{1 - e}

Verify Solutions:

x = \frac{e}{1 - e}

False

The solution is

No Solution for x \in R

x, lo g_{3} (x + 5) = 2

lo g_{10} (x^{2} - 4 x + 5) = 0

ln (x) = lo g_{x} (e)

lo g_{3} (x + 2) - lo g_{9} (x) = 1

0.34 = ln (y)

What is the answer to solvefor x,ln(x)-ln(x+1)=1 ?
The answer to solvefor x,ln(x)-ln(x+1)=1 is No Solution for x\in\mathbb{R}