What is the answer to log_{3}(x+2)-log_{9}(x)=1 ?

The answer to log_{3}(x+2)-log_{9}(x)=1 is x=4,x=1

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log_{3}(x+2)-log_{9}(x)=1

lo g_{3} (x + 2) - lo g_{9} (x) = 1

x = 4, x = 1

Solution steps

lo g_{3} (x + 2) - lo g_{9} (x) = 1

Apply log rules

(x + 2)^{2} = 9 x

Solve

(x + 2)^{2} = 9 x : x = 4, x = 1

x = 4, x = 1

Verify Solutions:

x = 4

True

, x = 1

True

The solutions are

x = 4, x = 1

0.34 = ln (y)

lo g_{2} ((r + 9)^{2}) = 6

lo g_{3} (10 - x) - lo g_{3} (x + 2) = 1

lo g_{10} (y^{10}) = 2

2 lo g_{10} (x) + 1 = 5

What is the answer to log_{3}(x+2)-log_{9}(x)=1 ?
The answer to log_{3}(x+2)-log_{9}(x)=1 is x=4,x=1
Solve for x: log_{3}(x+2)-log_{9}(x)=1
The solution is x=4,x=1