What is the answer to log_{10}(x)=-2.62 ?

The answer to log_{10}(x)=-2.62 is x= 1/(10^{2.62)}

Solve for x: log_{10}(x)=-2.62

The solution is x= 1/(10^{2.62)}

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lo g_{10} (x) = - 2.62

x = \frac{1}{1 0 ^{2.62}}

Solution steps

lo g_{10} (x) = - 2.62

Apply log rules

x = \frac{1}{1 0 ^{2.62}}

5.25 = lo g_{10} (x)

ln (\frac{x}{3}) = 4

2 lo g_{5} (5 x) - 1 = 11

lo g_{10} (2) + lo g_{10} (x) = 2

ln (7) + ln (x + 3) = lo g_{e} (2 x + 6)

What is the answer to log_{10}(x)=-2.62 ?
The answer to log_{10}(x)=-2.62 is x= 1/(10^{2.62)}
Solve for x: log_{10}(x)=-2.62
The solution is x= 1/(10^{2.62)}