What is the answer to log_{x+3}(2x^2-5x+9)=2 ?

The answer to log_{x+3}(2x^2-5x+9)=2 is x=11,x=0

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log_{x+3}(2x^2-5x+9)=2

lo g_{x + 3} (2 x^{2} - 5 x + 9) = 2

x = 11, x = 0

Solution steps

lo g_{x + 3} (2 x^{2} - 5 x + 9) = 2

Apply log rules

\frac{ln ( 2 x ^{2} - 5 x + 9 )}{ln ( x + 3 )} = 2

Multiply both sides by

ln (x + 3)

\frac{ln ( 2 x ^{2} - 5 x + 9 )}{ln ( x + 3 )} ln (x + 3) = 2 ln (x + 3)

Simplify

ln (2 x^{2} - 5 x + 9) = 2 ln (x + 3)

Apply log rules

2 x^{2} - 5 x + 9 = (x + 3)^{2}

Solve

2 x^{2} - 5 x + 9 = (x + 3)^{2} : x = 11, x = 0

x = 11, x = 0

Verify Solutions:

x = 11

True

, x = 0

True

The solutions are

x = 11, x = 0

6 + 5 ln (x) = 3

lo g_{2} (x) = lo g_{8} (15)

lo g_{2} (2 x) + lo g_{2} (2) = 3

lo g_{6} (x + 6) + lo g_{6} (x + 3) = 2

lo g_{x} (0.5) = 0.5

What is the answer to log_{x+3}(2x^2-5x+9)=2 ?
The answer to log_{x+3}(2x^2-5x+9)=2 is x=11,x=0
Solve for x: log_{x+3}(2x^2-5x+9)=2
The solution is x=11,x=0