What is the answer to log_{6}(x+6)+log_{6}(x+3)=2 ?

The answer to log_{6}(x+6)+log_{6}(x+3)=2 is x=(-9+3sqrt(17))/2

Solve for x: log_{6}(x+6)+log_{6}(x+3)=2

The solution is x=(-9+3sqrt(17))/2

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lo g_{6} (x + 6) + lo g_{6} (x + 3) = 2

x = \frac{- 9 + 3 17}{2}

Solution steps

lo g_{6} (x + 6) + lo g_{6} (x + 3) = 2

Apply log rules

(x + 6) (x + 3) = 36

Solve

(x + 6) (x + 3) = 36 : x = \frac{- 9 + 3 17}{2}, x = \frac{- 9 - 3 17}{2}

x = \frac{- 9 + 3 17}{2}, x = \frac{- 9 - 3 17}{2}

Verify Solutions:

x = \frac{- 9 + 3 17}{2}

True

, x = \frac{- 9 - 3 17}{2}

False

The solution is

x = \frac{- 9 + 3 17}{2}

lo g_{x} (0.5) = 0.5

lo g_{2} (5 x) + 2 lo g_{2} (7) = 3

lo g_{3} (x - 1) + lo g_{3} (x + 1) = 1

- 10 = 20 lo g_{10} (x)

lo g_{36} (6^{a}) = a + 1

What is the answer to log_{6}(x+6)+log_{6}(x+3)=2 ?
The answer to log_{6}(x+6)+log_{6}(x+3)=2 is x=(-9+3sqrt(17))/2
Solve for x: log_{6}(x+6)+log_{6}(x+3)=2
The solution is x=(-9+3sqrt(17))/2