What is the answer to log_{3}(8x)-log_{3}(4)=4 ?

The answer to log_{3}(8x)-log_{3}(4)=4 is x= 81/2

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log_{3}(8x)-log_{3}(4)=4

lo g_{3} (8 x) - lo g_{3} (4) = 4

x = \frac{81}{2}

Decimal Notation

x = 40.5

Solution steps

lo g_{3} (8 x) - lo g_{3} (4) = 4

Move

lo g_{3} (4)

to the right side

lo g_{3} (8 x) = 4 + lo g_{3} (4)

Apply log rules

8 x = 324

Solve

8 x = 324 : x = \frac{81}{2}

x = \frac{81}{2}

Verify Solutions:

x = \frac{81}{2}

True

The solution is

x = \frac{81}{2}

6 = 7.2 + lo g_{10} (x)

lo g_{16} (x) = (lo g_{4} (x^{2}))

20 \cdot lo g_{10} (x) = - 3

lo g_{10} (x) = 3.58

- \frac{( ln ( x ) )}{x ^{2}} = 0

What is the answer to log_{3}(8x)-log_{3}(4)=4 ?
The answer to log_{3}(8x)-log_{3}(4)=4 is x= 81/2
Solve for x: log_{3}(8x)-log_{3}(4)=4
The solution is x= 81/2