What are the solutions to the equation -2x^2+10x+23=0 ?

The solutions to the equation -2x^2+10x+23=0 are x=-(-5+sqrt(71))/2 ,x=(5+sqrt(71))/2

Find the zeros of -2x^2+10x+23=0

The zeros of -2x^2+10x+23=0 are x=-(-5+sqrt(71))/2 ,x=(5+sqrt(71))/2

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- 2 x^{2} + 10 x + 23 = 0

x = - \frac{- 5 + 71}{2}, x = \frac{5 + 71}{2}

Solution steps

- 2 x^{2} + 10 x + 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 2 ) \cdot 23}{2 ( - 2 )}

1 0^{2} - 4 (- 2) \cdot 23 = 271

x_{1, 2} = \frac{- 10 \pm 2 71}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 10 + 2 71}{2 ( - 2 )}, x_{2} = \frac{- 10 - 2 71}{2 ( - 2 )}

x = \frac{- 10 + 2 71}{2 ( - 2 )} : - \frac{- 5 + 71}{2}

x = \frac{- 10 - 2 71}{2 ( - 2 )} : \frac{5 + 71}{2}

The solutions to the quadratic equation are:

x = - \frac{- 5 + 71}{2}, x = \frac{5 + 71}{2}

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What are the solutions to the equation -2x^2+10x+23=0 ?
The solutions to the equation -2x^2+10x+23=0 are x=-(-5+sqrt(71))/2 ,x=(5+sqrt(71))/2
Find the zeros of -2x^2+10x+23=0
The zeros of -2x^2+10x+23=0 are x=-(-5+sqrt(71))/2 ,x=(5+sqrt(71))/2