What are the solutions to the equation -2x^2+10x+23=0 ?

The solutions to the equation -2x^2+10x+23=0 are x=-(-5+sqrt(71))/2 ,x=(5+sqrt(71))/2

Find the zeros of -2x^2+10x+23=0

The zeros of -2x^2+10x+23=0 are x=-(-5+sqrt(71))/2 ,x=(5+sqrt(71))/2

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- 2 x^{2} + 10 x + 23 = 0

x = - \frac{- 5 + 71}{2}, x = \frac{5 + 71}{2}

Decimal Notation

x = - 1.71307 \dots, x = 6.71307 \dots

Solution steps

- 2 x^{2} + 10 x + 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 2 ) \cdot 23}{2 ( - 2 )}

1 0^{2} - 4 (- 2) \cdot 23 = 271

x_{1, 2} = \frac{- 10 \pm 2 71}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 10 + 2 71}{2 ( - 2 )}, x_{2} = \frac{- 10 - 2 71}{2 ( - 2 )}

x = \frac{- 10 + 2 71}{2 ( - 2 )} : - \frac{- 5 + 71}{2}

x = \frac{- 10 - 2 71}{2 ( - 2 )} : \frac{5 + 71}{2}

The solutions to the quadratic equation are:

x = - \frac{- 5 + 71}{2}, x = \frac{5 + 71}{2}

2 x + 3 (x - 4)^{2} = 37 + (x - 3) (x + 3)

5175

2 x^{2} - 4 x + 5 = 0

6 g^{3} + 18 g^{2} + 5 g + 15

1.3 \cdot 2

What are the solutions to the equation -2x^2+10x+23=0 ?
The solutions to the equation -2x^2+10x+23=0 are x=-(-5+sqrt(71))/2 ,x=(5+sqrt(71))/2
Find the zeros of -2x^2+10x+23=0
The zeros of -2x^2+10x+23=0 are x=-(-5+sqrt(71))/2 ,x=(5+sqrt(71))/2