What is the answer to log_{2}(x+1)=log_{10}(13) ?

The answer to log_{2}(x+1)=log_{10}(13) is x=2^{log_{10}(13)}-1

Solve for x: log_{2}(x+1)=log_{10}(13)

The solution is x=2^{log_{10}(13)}-1

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lo g_{2} (x + 1) = lo g_{10} (13)

x = 2^{l o g_{10} (13)} - 1

Decimal Notation

x = 1.16436 \dots

Solution steps

lo g_{2} (x + 1) = lo g_{10} (13)

Apply log rules

x + 1 = 2^{l o g_{10} (13)}

Solve

x + 1 = 2^{l o g_{10} (13)} : x = 2^{l o g_{10} (13)} - 1

x = 2^{l o g_{10} (13)} - 1

lo g_{2} (9 x) + 2 lo g_{2} (8) = 3

lo g_{4} (x - 3) = - lo g_{4} (x - 6) + 1

ln (3 x - 15) = 6

lo g_{3} (x + 2) - lo g_{3} (x) = 2

lo g_{x} (6) = \frac{1}{3}

What is the answer to log_{2}(x+1)=log_{10}(13) ?
The answer to log_{2}(x+1)=log_{10}(13) is x=2^{log_{10}(13)}-1
Solve for x: log_{2}(x+1)=log_{10}(13)
The solution is x=2^{log_{10}(13)}-1