What is the answer to log_{10}(x)+log_{10}(4x)=2 ?

The answer to log_{10}(x)+log_{10}(4x)=2 is x=10^{(2-2log_{10}(2))/2}

Solve for x: log_{10}(x)+log_{10}(4x)=2

The solution is x=10^{(2-2log_{10}(2))/2}

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lo g_{10} (x) + lo g_{10} (4 x) = 2

x = 1 0^{\frac{2 - 2 l o g _{10} ( 2 )}{2}}

Decimal Notation

x = 5

Solution steps

lo g_{10} (x) + lo g_{10} (4 x) = 2

Apply log rules

x = 1 0^{\frac{2 - 2 l o g _{10} ( 2 )}{2}}

Verify Solutions:

x = 1 0^{\frac{2 - 2 l o g _{10} ( 2 )}{2}}

True

The solution is

x = 1 0^{\frac{2 - 2 l o g _{10} ( 2 )}{2}}

4 + 3 ln (x) = 5

ln (x) = ln (2 x - 1) - ln (x - 2)

- 3 lo g_{7} (- 5 n - 7) = 0

ln^{2} (x) - 3 ln (x) + 2 = 0

1 + lo g_{6} (x) = lo g_{6} (2 x + 4)

What is the answer to log_{10}(x)+log_{10}(4x)=2 ?
The answer to log_{10}(x)+log_{10}(4x)=2 is x=10^{(2-2log_{10}(2))/2}
Solve for x: log_{10}(x)+log_{10}(4x)=2
The solution is x=10^{(2-2log_{10}(2))/2}