What is the answer to log_{x}(1/125)=-9 ?

The answer to log_{x}(1/125)=-9 is x=e^{(ln(5))/3}

Solve for x: log_{x}(1/125)=-9

The solution is x=e^{(ln(5))/3}

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lo g_{x} (\frac{1}{125}) = - 9

x = e^{\frac{l n ( 5 )}{3}}

Solution steps

lo g_{x} (\frac{1}{125}) = - 9

Apply log rules

\frac{ln ( \frac{1}{125} )}{ln ( x )} = - 9

Multiply both sides by

ln (x)

\frac{ln ( \frac{1}{125} )}{ln ( x )} ln (x) = - 9 ln (x)

Apply log rules

x = e^{\frac{l n ( 5 )}{3}}

Verify Solutions:

x = e^{\frac{l n ( 5 )}{3}}

True

The solution is

x = e^{\frac{l n ( 5 )}{3}}

lo g_{10} (x + 3) = 0

0.74 = ln (y)

- 2 = lo g_{0.1} (x)

lo g_{2} (2 x - 3) = lo g_{2} (7)

lo g_{10} (x^{- 1}) = n

What is the answer to log_{x}(1/125)=-9 ?
The answer to log_{x}(1/125)=-9 is x=e^{(ln(5))/3}
Solve for x: log_{x}(1/125)=-9
The solution is x=e^{(ln(5))/3}