What is the answer to log_{2}(2x-3)=log_{2}(7) ?

The answer to log_{2}(2x-3)=log_{2}(7) is x=5

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log_{2}(2x-3)=log_{2}(7)

lo g_{2} (2 x - 3) = lo g_{2} (7)

x = 5

Solution steps

lo g_{2} (2 x - 3) = lo g_{2} (7)

Apply log rules

2 x - 3 = 7

Solve

2 x - 3 = 7 : x = 5

x = 5

Verify Solutions:

x = 5

True

The solution is

x = 5

lo g_{10} (x^{- 1}) = n

3 lo g_{10} (3 x - 2) = 3

lo g_{10} (x) = - x + 3

lo g_{5} (x - 4) = 3

x, t = lo g_{2} (x)

What is the answer to log_{2}(2x-3)=log_{2}(7) ?
The answer to log_{2}(2x-3)=log_{2}(7) is x=5
Solve for x: log_{2}(2x-3)=log_{2}(7)
The solution is x=5