What is the answer to log_{10}(x)=-x+3 ?

The answer to log_{10}(x)=-x+3 is x=(\W_{0}(1000ln(10)))/(ln(10))

Solve for x: log_{10}(x)=-x+3

The solution is x=(\W_{0}(1000ln(10)))/(ln(10))

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lo g_{10} (x) = - x + 3

x = \frac{W _{0} ( 1000 ln ( 10 ) )}{ln ( 10 )}

Solution steps

lo g_{10} (x) = - x + 3

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

1 0^{l o g_{10} (x)} = 1 0^{- x + 3}

Simplify

1 0^{l o g_{10} (x)} : x

x = 1 0^{- x + 3}

Solve

x = 1 0^{- x + 3} : x = \frac{W _{0} ( 1000 ln ( 10 ) )}{ln ( 10 )}

x = \frac{W _{0} ( 1000 ln ( 10 ) )}{ln ( 10 )}

Verify Solutions:

x = \frac{W _{0} ( 1000 ln ( 10 ) )}{ln ( 10 )}

True

The solution is

x = \frac{W _{0} ( 1000 ln ( 10 ) )}{ln ( 10 )}

lo g_{5} (x - 4) = 3

x, t = lo g_{2} (x)

ln (x^{2} - x) = 0

2 lo g_{10} (3 x) = 0

0.61 = ln (x)

What is the answer to log_{10}(x)=-x+3 ?
The answer to log_{10}(x)=-x+3 is x=(\W_{0}(1000ln(10)))/(ln(10))
Solve for x: log_{10}(x)=-x+3
The solution is x=(\W_{0}(1000ln(10)))/(ln(10))