What is the answer to ln(x^2-x)=0 ?

The answer to ln(x^2-x)=0 is x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2

Solve for x: ln(x^2-x)=0

The solution is x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2

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ln (x^{2} - x) = 0

x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

Solution steps

ln (x^{2} - x) = 0

Apply log rules

x^{2} - x = 1

Solve

x^{2} - x = 1 : x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

x = \frac{1 + 5}{2}, x = \frac{1 - 5}{2}

2 lo g_{10} (3 x) = 0

0.61 = ln (x)

lo g_{10} (\frac{x + 1}{2}) = 3

lo g_{10} (3 x) = ln (x)

ln (x - 2) = 3 ln (2) + 2

What is the answer to ln(x^2-x)=0 ?
The answer to ln(x^2-x)=0 is x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2
Solve for x: ln(x^2-x)=0
The solution is x=(1+sqrt(5))/2 ,x=(1-sqrt(5))/2