What is the answer to log_{10}(3x)=ln(x) ?

The answer to log_{10}(3x)=ln(x) is x= 1/(10^{(log_{10)(3)log_{10}(e))/(log_{10)(e)-1}}}

Solve for x: log_{10}(3x)=ln(x)

The solution is x= 1/(10^{(log_{10)(3)log_{10}(e))/(log_{10)(e)-1}}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{10} (3 x) = ln (x)

x = \frac{1}{1 0 ^{\frac{l o g _{10} ( 3 ) l o g _{10} ( e )}{l o g _{10} ( e ) - 1}}}

Solution steps

lo g_{10} (3 x) = ln (x)

Apply log rules

x = \frac{1}{1 0 ^{\frac{l o g _{10} ( 3 ) l o g _{10} ( e )}{l o g _{10} ( e ) - 1}}}

Verify Solutions:

x = \frac{1}{1 0 ^{\frac{l o g _{10} ( 3 ) l o g _{10} ( e )}{l o g _{10} ( e ) - 1}}}

True

The solution is

x = \frac{1}{1 0 ^{\frac{l o g _{10} ( 3 ) l o g _{10} ( e )}{l o g _{10} ( e ) - 1}}}

ln (x - 2) = 3 ln (2) + 2

2 ln (x + 3) - ln (x) = ln (x + 3 a)

y, ln (y) = - 6 x^{2}

lo g_{4} (5 x + 4) - lo g_{4} (4 - x) = 1

50 = 1200 \cdot lo g_{2} (x)

What is the answer to log_{10}(3x)=ln(x) ?
The answer to log_{10}(3x)=ln(x) is x= 1/(10^{(log_{10)(3)log_{10}(e))/(log_{10)(e)-1}}}
Solve for x: log_{10}(3x)=ln(x)
The solution is x= 1/(10^{(log_{10)(3)log_{10}(e))/(log_{10)(e)-1}}}