What is the answer to 2log_{3}(x)=2+log_{3}(x-2) ?

The answer to 2log_{3}(x)=2+log_{3}(x-2) is x=6,x=3

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2log_{3}(x)=2+log_{3}(x-2)

2 lo g_{3} (x) = 2 + lo g_{3} (x - 2)

x = 6, x = 3

Solution steps

2 lo g_{3} (x) = 2 + lo g_{3} (x - 2)

Apply log rules

x^{2} = 9 (x - 2)

Solve

x^{2} = 9 (x - 2) : x = 6, x = 3

x = 6, x = 3

Verify Solutions:

x = 6

True

, x = 3

True

The solutions are

x = 6, x = 3

ln (4 + a e^{b t}) = 0

ln (x + 5) = ln (x - 1) + ln (x + 1)

- 3 = 20 lo g_{10} (\frac{1}{x})

lo g_{2} (x^{2} + 3 x - 2) = 1

lo g_{x} (x) + lo g_{10} (8) = 2

What is the answer to 2log_{3}(x)=2+log_{3}(x-2) ?
The answer to 2log_{3}(x)=2+log_{3}(x-2) is x=6,x=3
Solve for x: 2log_{3}(x)=2+log_{3}(x-2)
The solution is x=6,x=3