What is the answer to log_{2}(z+7)+log_{2}(z+5)=3 ?

The answer to log_{2}(z+7)+log_{2}(z+5)=3 is z=-3

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log_{2}(z+7)+log_{2}(z+5)=3

lo g_{2} (z + 7) + lo g_{2} (z + 5) = 3

z = - 3

Solution steps

lo g_{2} (z + 7) + lo g_{2} (z + 5) = 3

Apply log rules

(z + 7) (z + 5) = 8

Solve

(z + 7) (z + 5) = 8 : z = - 3, z = - 9

z = - 3, z = - 9

Verify Solutions:

z = - 3

True

, z = - 9

False

The solution is

z = - 3

ln (x) + 0.5 = ln (x)

4 lo g_{x} (3) - lo g_{3} (x^{2}) = 7

u, ln (u) = x + c

1.01885 = 0.6446 ln (x) - 0.5557

lo g_{5} (m) + lo g_{5} (m + 20) = 3

What is the answer to log_{2}(z+7)+log_{2}(z+5)=3 ?
The answer to log_{2}(z+7)+log_{2}(z+5)=3 is z=-3
Solve for z: log_{2}(z+7)+log_{2}(z+5)=3
The solution is z=-3