What is the answer to log_{5}(m)+log_{5}(m+20)=3 ?

The answer to log_{5}(m)+log_{5}(m+20)=3 is m=5

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log_{5}(m)+log_{5}(m+20)=3

lo g_{5} (m) + lo g_{5} (m + 20) = 3

m = 5

Solution steps

lo g_{5} (m) + lo g_{5} (m + 20) = 3

Apply log rules

m (m + 20) = 125

Solve

m (m + 20) = 125 : m = 5, m = - 25

m = 5, m = - 25

Verify Solutions:

m = 5

True

, m = - 25

False

The solution is

m = 5

lo g_{2} (3 x - 1) = lo g_{2} (x - 5) + 2

lo g_{9} (x) - lo g_{3} (x) = 2

ln (x) + ln (9) = ln (18)

lo g_{27} (2 x - 1) = \frac{4}{3}

lo g_{2} (x) = lo g_{x} (2) + 2

What is the answer to log_{5}(m)+log_{5}(m+20)=3 ?
The answer to log_{5}(m)+log_{5}(m+20)=3 is m=5
Solve for m: log_{5}(m)+log_{5}(m+20)=3
The solution is m=5