What is the answer to log_{2}(3x-1)=log_{2}(x-5)+2 ?

The answer to log_{2}(3x-1)=log_{2}(x-5)+2 is x=19

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log_{2}(3x-1)=log_{2}(x-5)+2

lo g_{2} (3 x - 1) = lo g_{2} (x - 5) + 2

x = 19

Solution steps

lo g_{2} (3 x - 1) = lo g_{2} (x - 5) + 2

Apply log rules

3 x - 1 = (x - 5) \cdot 4

Solve

3 x - 1 = (x - 5) \cdot 4 : x = 19

x = 19

Verify Solutions:

x = 19

True

The solution is

x = 19

lo g_{9} (x) - lo g_{3} (x) = 2

ln (x) + ln (9) = ln (18)

lo g_{27} (2 x - 1) = \frac{4}{3}

lo g_{2} (x) = lo g_{x} (2) + 2

lo g_{10} (x - 5) = 17

What is the answer to log_{2}(3x-1)=log_{2}(x-5)+2 ?
The answer to log_{2}(3x-1)=log_{2}(x-5)+2 is x=19
Solve for x: log_{2}(3x-1)=log_{2}(x-5)+2
The solution is x=19