What is the answer to log_{27}(a^2)=9 ?

The answer to log_{27}(a^2)=9 is a=1594323sqrt(3),a=-1594323sqrt(3)

Solve for a: log_{27}(a^2)=9

The solution is a=1594323sqrt(3),a=-1594323sqrt(3)

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lo g_{27} (a^{2}) = 9

a = 15943233, a = - 15943233

Decimal Notation

a = 2761448.43967 \dots, a = - 2761448.43967 \dots

Solution steps

lo g_{27} (a^{2}) = 9

Apply log rules

a^{2} = 2 7^{9}

Solve

a^{2} = 2 7^{9} : a = 15943233, a = - 15943233

a = 15943233, a = - 15943233

x, 3 = - lo g_{10} (x)

lo g_{x} (x + 12) = 2

lo g_{x + 1} (5 x + 19) = 2

lo g_{13} (- x) + 5 = 8

ln (x) = 6.188235491

What is the answer to log_{27}(a^2)=9 ?
The answer to log_{27}(a^2)=9 is a=1594323sqrt(3),a=-1594323sqrt(3)
Solve for a: log_{27}(a^2)=9
The solution is a=1594323sqrt(3),a=-1594323sqrt(3)