What is the answer to log_{x+1}(5x+19)=2 ?

The answer to log_{x+1}(5x+19)=2 is x=6

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log_{x+1}(5x+19)=2

lo g_{x + 1} (5 x + 19) = 2

x = 6

Solution steps

lo g_{x + 1} (5 x + 19) = 2

Apply log rules

\frac{ln ( 5 x + 19 )}{ln ( x + 1 )} = 2

Multiply both sides by

ln (x + 1)

\frac{ln ( 5 x + 19 )}{ln ( x + 1 )} ln (x + 1) = 2 ln (x + 1)

Simplify

ln (5 x + 19) = 2 ln (x + 1)

Apply log rules

5 x + 19 = (x + 1)^{2}

Solve

5 x + 19 = (x + 1)^{2} : x = 6, x = - 3

x = 6, x = - 3

Verify Solutions:

x = 6

True

, x = - 3

False

The solution is

x = 6

lo g_{13} (- x) + 5 = 8

ln (x) = 6.188235491

lo g_{3} (5 x - 1) = lo g_{3} (x + 7)

lo g_{8} (3) + lo g_{8} (- 4 x) = 1

lo g_{6} (x + 1) + lo g_{6} (x + 2) = 1

What is the answer to log_{x+1}(5x+19)=2 ?
The answer to log_{x+1}(5x+19)=2 is x=6
Solve for x: log_{x+1}(5x+19)=2
The solution is x=6