What is the answer to log_{3}(5x-1)=log_{3}(x+7) ?

The answer to log_{3}(5x-1)=log_{3}(x+7) is x=2

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log_{3}(5x-1)=log_{3}(x+7)

lo g_{3} (5 x - 1) = lo g_{3} (x + 7)

x = 2

Solution steps

lo g_{3} (5 x - 1) = lo g_{3} (x + 7)

Apply log rules

5 x - 1 = x + 7

Solve

5 x - 1 = x + 7 : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

lo g_{8} (3) + lo g_{8} (- 4 x) = 1

lo g_{6} (x + 1) + lo g_{6} (x + 2) = 1

lo g_{32} (m) = \frac{1}{5}

lo g_{2} (6 x + 3) = 5

lo g_{5} (x^{4}) + lo g_{5} (x) = 8

What is the answer to log_{3}(5x-1)=log_{3}(x+7) ?
The answer to log_{3}(5x-1)=log_{3}(x+7) is x=2
Solve for x: log_{3}(5x-1)=log_{3}(x+7)
The solution is x=2