What is the answer to ln(4-x^2)=0 ?

The answer to ln(4-x^2)=0 is x=sqrt(3),x=-sqrt(3)

Solve for x: ln(4-x^2)=0

The solution is x=sqrt(3),x=-sqrt(3)

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ln (4 - x^{2}) = 0

x = 3, x = - 3

Decimal Notation

x = 1.73205 \dots, x = - 1.73205 \dots

Solution steps

ln (4 - x^{2}) = 0

Apply log rules

4 - x^{2} = 1

Solve

4 - x^{2} = 1 : x = 3, x = - 3

x = 3, x = - 3

2 ln (x) - 2 ln (2) = ln (9)

lo g_{6} (x) + lo g_{6} (x) - 9 = 2

12 lo g_{x} (2) + lo g_{2} (x) - 7 = 0

ln (b) = 3

0 = lo g_{5} (x - 1) + 4

What is the answer to ln(4-x^2)=0 ?
The answer to ln(4-x^2)=0 is x=sqrt(3),x=-sqrt(3)
Solve for x: ln(4-x^2)=0
The solution is x=sqrt(3),x=-sqrt(3)