What is the answer to log_{6}(x)+log_{6}(x)-9=2 ?

The answer to log_{6}(x)+log_{6}(x)-9=2 is x=7776sqrt(6)

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log_{6}(x)+log_{6}(x)-9=2

lo g_{6} (x) + lo g_{6} (x) - 9 = 2

x = 77766

Decimal Notation

x = 19047.23223 \dots

Solution steps

lo g_{6} (x) + lo g_{6} (x) - 9 = 2

Add similar elements:

lo g_{6} (x) + lo g_{6} (x) = 2 lo g_{6} (x)

2 lo g_{6} (x) - 9 = 2

Move

9

to the right side

2 lo g_{6} (x) = 11

Divide both sides by

2

lo g_{6} (x) = \frac{11}{2}

Apply log rules

x = 77766

Verify Solutions:

x = 77766

True

The solution is

x = 77766

12 lo g_{x} (2) + lo g_{2} (x) - 7 = 0

ln (b) = 3

0 = lo g_{5} (x - 1) + 4

lo g_{8} (x) = (\frac{1}{3})

lo g_{3} (x + 4) = 1 + lo g_{3} (x - 2)

What is the answer to log_{6}(x)+log_{6}(x)-9=2 ?
The answer to log_{6}(x)+log_{6}(x)-9=2 is x=7776sqrt(6)
Solve for x: log_{6}(x)+log_{6}(x)-9=2
The solution is x=7776sqrt(6)